Question

The oxidation number of iodine in each of the following compounds, $I{F}_7,I{F}_5,KI,I_2,ICI$ and $HI{O}_4$ respectively, is :

• A. $+7,+5,-1,0,+1,+7$
• B. $+7,+5,-1,0,+2,+7$
• C. $+7,+5,-1,0,+4,+7$
• D. none of these

Answer 1

The correct option is A $+7,+5,-1,0,+1,+7$

Let $x$ be the oxidation number of iodine.
Since, the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
$I{F}_7$; $x+7(-1)=0;x=+7$
$I{F}_5$; $x+5(-1)=0;x=+5$
$KI$; $1+x=0;x=-1$
$I_2$; $2x=0;x=0$
$ICI$; $x-1=0;x=+1$
$HI{O}_4$; $1+x+4(-2)=0;x=+7$
The oxidation number of iodine in $I{F}_7,I{F}_5,KI,I_2,ICI$ and $HI{O}_4$ is $+7,+5,-1,0,+1$ and $+7$ respectively.