The oxidation number of manganese in potassium manganate is:

+ 7

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+ 6

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+ 4

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+ 2

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Solution

The correct option is B $+ 6$
$K_{2} M n O_{4}$ : Potassium manganate.

For 2 $K^{+}$ , the oxidation state is $+ 2$ .

For $M n O_{4}^{2 -}$ ; $M n + 4 \times - 2 = - 2$ or, $x = + 6$ .

therefore, $M n$ has the oxidation state of $+ 6$ .

Option B is correct.

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