The oxidation number of Mn in the product of alkaline oxidative fusion of $M n O_{2}$ is:

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Solution

$2 M n O_{2} + 4 K O H + O_{2} \to 2 K_{2} M n O_{4} + 2 H_{2} O$

Oxidation state of Mn in $K_{2} M n O_{4} = 2 + x + (- 8) = 0$

$\Rightarrow x = + 6$

Oxidation state of $M n = + 6$ in $K_{2} M n O_{4}$ .
(Potassium manganate)

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