You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Oxidation Number Method

The oxidation...

Question

The oxidation number of N and $C l$ in $N O C l O_{4}$ respectively are :

+2 and +7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+3 and +7

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-3 and +5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+2 and -7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A +3 and +7
$N O C l O_{4}$ is actually ${N O}^{+} {C l O}_{4}^{-}$ .

Let the oxidation state of N in ${N O}^{+}$ is.

$x + (- 2) = + 1$

$x = + 1 + 2 = + 3$

Let the oxidation state of $C l$ in ${C l O}_{4}^{-}$ is y.

$y + (- 2) \times 4 = - 1$

$y - 8 = - 1; y = + 7$

Suggest Corrections

Similar questions

Q. The formal oxidation numbers of Cr and Cl in the ions

C r_{2} O_{7}^{2 -}

and

C l O_{3}^{-}

respectively, are

Q. Oxidation number of chlorine

(C l)

atoms in

H C l O_{4}

and

H C l O_{3}

molecules are :

Q. Predict the behaviour of both oxides

N a_{2} O

and

C l_{2} O_{7}

Q. What is the oxidation number of

M n

K M n O_{4}

and of

S

N a_{2} S_{2} O_{3}

Calculate the oxidation number of sulphur, chromium and nitrogen in $H_{2} S O_{5},$
$C r_{2} O_{7}^{2 -}$ and $N O_{3 -}^{-}$ . Suggest structure of these compounds. Count for the fallacy.

$x C r_{2} 2 - O_{7}^{2 -}$

$x N 2 - O_{3}^{-}$

Join BYJU'S Learning Program

The oxidation number of N and Cl in NOClO4 respectively are :

The correct option is A +3 and +7NOClO4 is actually NO+ClO−4.Let the oxidation state of N in NO+ is.x+(−2)=+1x=+1+2=+3Let the oxidation state of Cl in ClO−4 is y.y+(−2)×4=−1y−8=−1;y=+7

The oxidation number of N and $C l$ in $N O C l O_{4}$ respectively are :

The correct option is A +3 and +7
$N O C l O_{4}$ is actually ${N O}^{+} {C l O}_{4}^{-}$ .

Let the oxidation state of N in ${N O}^{+}$ is.

$x + (- 2) = + 1$

$x = + 1 + 2 = + 3$

Let the oxidation state of $C l$ in ${C l O}_{4}^{-}$ is y.

$y + (- 2) \times 4 = - 1$

$y - 8 = - 1; y = + 7$