Question

The oxidation number of nitrogen in $(N_2{H}_5{)}^{+}$ is:

• A. -2
• B. 2
• C. 3
• D. -3

Answer 1

The correct option is A -2

Let the oxidation number of nitrogen be $x$.

Oxidation number of $H=+1$

$(N_2{H}_5{)}^{+}$: $2\times x+5\times 1=+1$

$2x+5=1$ or $x=-2$

Thus Oxidation number of $N$ in $(N_2{H}_5{)}^{+}$ is +2