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Question

The oxidation number of oxygen in KO3,Na2O2 is:

A
3,2
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B
1,0
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C
0,1
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D
0.33,1
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Solution

The correct option is C 0.33,1
KO3
Suppose oxidation number of O=x, 1+3x=0
3x=1
x=13=0.33
Na2O2
Suppose oxidation number of O=x
2×1+2x=0
2+2x=0
2x=2x=22
x=1

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