CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The oxidation number of oxygen in KO3,Na2O2 is:

A
3,2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1,0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0,1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.33,1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C 0.33,1
KO3
Suppose oxidation number of O=x, 1+3x=0
3x=1
x=13=0.33
Na2O2
Suppose oxidation number of O=x
2×1+2x=0
2+2x=0
2x=2x=22
x=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Oxidation Number and State
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon