The oxidation number of oxygen is $- 1$ in:

N O_{2}

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P b O_{2}

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N a_{2} O_{2}

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M n O_{2}

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Solution

The correct option is D $N a_{2} O_{2}$
The oxidation number of oxygen is $- 1$ in sodium peroxide $N a_{2} O_{2}$ .

In peroxides, O has $- 1$ oxidation number.

Hence, option $C$ is correct.

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Similar questions

O F_{2}, O_{2}, N a_{2} O_{2}

C H_{3} C O O H

The oxidation state of oxygen in $K O_{3}$ , $N a_{2} O_{2}$ are respectively :

K O_{3}

N a_{2} O_{2}

{P b O}_{2}

{M n O}_{2}

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