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Question

The oxidation number of phosphorous in PO3−4, P4O10 and P2O4−7 is :

A
+5
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B
+3
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C
3
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D
+2
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Solution

The correct option is A +5
The oxidation number of phosphorous in PO34,P4O10 and P2O47 is +5.
Let X be the oxidation number of P in PO34.
X+4(2)=3
X=+5
Let X be the oxidation number of P inP4.O10
4X+10(2)=0
X=+5
Let X be the oxidation number of P inP2O47.
2X+7(2)=4
X=+5

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