The oxidation number of Phosphorus in $M g_{2} P_{2} O_{7}$ is:

+ 3

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+ 2

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+ 5

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- 3

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Solution

The correct option is C + 5
Mg has o.n. = +2 and O has o.n. = -2
( 22 ) + 2x + ( 7 -2) = 0
4 + 2x - 14 = 0
2x = 10
x = +5 ( o.n. of P)

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