The oxidation number of $P t$ in $[P t (C_{2} H_{4}) C l_{3}]^{-}$ is:

+ 1

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+ 2

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+ 3

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+ 4

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Solution

The correct option is C $+ 2$
$[P t (C_{2} H_{4}) c l_{3}]^{-}$

oxidation no. of $C_{2} H_{4} = 0$
oxidation no. of $c l = - 1$
$∴ x + 0 + 3 (- 1) = - 1$
$\Rightarrow x = + 2$
$\Rightarrow$ oxidation no. of $p t = + 2$

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