The oxidation number of Pt in $[P t (C_{2} H_{4}) C l_{3}]^{-}$ is :

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Solution

The correct option is D 2
Let oxidation state of Pt be $x$ in $[P t C_{2} H_{4}) C l_{3}]^{-}$ .
Since the overall charge on the complex is $- 1$ , the sum of oxidation states of all elements in it should be equal to $- 1$ .
Therefore, $x + 0 - 3 = - 1$
or, $x = + 2$

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