Question

The oxidation number of $Fe$ in ${Fe}_{0.94}O$ is :

• A. $200$
• B. $\frac{200}{94}$
• C. $\frac{94}{200}$
• D. none

Answer 1

The correct option is B $\frac{200}{94}$

Let $x$ be the oxidation state of $Fe$ in ${Fe}_{0.94}O$.
Since the overall charge on the compound is $0$, the sum of oxidation states of all elements must be equal to $0$.
$x\times 0.94-2=0$
$\therefore x=\frac{2}{0.94}=\frac{200}{94}$
Oxidation state of $Fe=\frac{200}{94}$.