The oxidation number of - S - in CH 32 SO is-A- 2B- 1C- 0D- 3

The correct option is C 0 Let the oxidation number of S is 'a'. O.N. of CH_3 and O = +1 and nbsp; 2 respectively. Since the molecule is neutral so, (2×(+1)) ...

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Standard XII

Chemistry

Assigning Oxidation Numbers

The oxidation...

Question

The oxidation number of $^{'} S^{'}$ in $(C H_{3})_{2} S O$ is:

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0.0

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Solution

The correct option is C 0.0

Let the oxidation number of $S$ is 'a'.
O.N. of $C H_{3}$ and $O$ = +1 and -2 respectively.
Since the molecule is neutral so,
$(2 \times (+ 1)) + a + (- 2) = 0 a n d a = 0$

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The oxidation number of ′S′ in (CH3)2SO is:

The correct option is C 0.0 Let the oxidation number of S is 'a'. O.N. of CH3 and O = +1 and -2 respectively. Since the molecule is neutral so, (2×(+1))+a+(−2)=0 and a=0

The oxidation number of $^{'} S^{'}$ in $(C H_{3})_{2} S O$ is:

The correct option is C 0.0

Let the oxidation number of $S$ is 'a'.
O.N. of $C H_{3}$ and $O$ = +1 and -2 respectively.
Since the molecule is neutral so,
$(2 \times (+ 1)) + a + (- 2) = 0 a n d a = 0$