Question

The oxidation number of sulfur in $NaHS{O}_4$?

• A. 0
• B. 2
• C. -2
• D. 4
• E. 6

Answer 1

The correct option is E 6

Oxidation number of $S$ in $NaHS{O}_4$:

$\Rightarrow 1+1+x+(4\times -2)=0$

$\Rightarrow 2+x-8=0$

$\Rightarrow x=+6$.