Question

The oxidation number of sulphur in $H_2{SO}_4$ is :

• A. $4$
• B. $2$
• C. $6$
• D. Zero

Answer 1

Answer: (C)

$6$

For a compound $H_2{SO}_4$,

As net charge on compound is $0$

Charge on : $H=1$

$S=x$

$O=-2$

$1\left(2\right)+x+(-2)\left(4\right)=0$

$2+x-8=0$

$x=6$

Hence, option C is correct.