The oxidation number of sulphur in $H_{2} {S O}_{4}$ is :

4

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2

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6

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Zero

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Solution

The correct option is B $6$
For a compound $H_{2} {S O}_{4}$ ,

As net charge on compound is $0$
Charge on : $H = 1$
$S = x$
$O = - 2$
$1 (2) + x + (- 2) (4) = 0$
$2 + x - 8 = 0$
$x = 6$

Hence, option C is correct.

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