Question

The oxidation number of sulphur in $N{a}_2{S}_4{O}_6$ is :

• A. $-2.5$
• B. $+2.5$
• C. $-10$
• D. $+10$

Answer 1

Answer: (B)

$+2.5$

$N{a}_2{S}_4{O}_6$
Ocidation no. of S be x
$\therefore 2+4x-12=0$
$\therefore 4x=10$
$\therefore x=\frac{10}{4}=\frac{5}{2}$
$\therefore x=2.5$

Thus oxidation state of 'S' is +2.5