Question

The oxidation number of sulphur in $S_2{F}_2$ is :

Answer 1

Let $x$ be the oxidation state of $S$ in $S_2{F}_2$.
Since, the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore,
$2x+2(-1)=0$
or, $x=+1$.
Hence, the oxidation state of $S$ in $S_2{F}_2$ is $+1$.