The oxidation number of sulphur in sulphuric acid is

-2

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-3

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Solution

The correct option is D
+6
Let the oxidation number of sulphur in sulphuric acid $(H_{2} S O_{4})$ be x.

$2 (1) + x + 4 (- 2) = 0 x = + 6$

Hence, the correct answer is option (d).

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