Question

The oxidation number of underlined element in $\underset{–}{M{n}_3}{O}_4$ compound is :

• A. $\frac{8}{3}$
• B. $\frac{7}{3}$
• C. $\frac{8}{5}$
• D. none of these

Answer 1

The correct option is A $\frac{8}{3}$

Let $Mn$ have oxidation state of $x$.

We know that the oxidation state of oxygen is -2.

So, $3x+(-2)\times 4=0$

$3x=8$

$x=\frac{8}{3}$

Hence, oxidation state of $Mn$ is $\frac{8}{3}$.

The correct option is A.