Question

The oxidation number(s) of nitrogen in $N{H}_{4}N{O}_3$ is/are

• A. $-3$ & $+5$
• B. $+3$ & $+5$
• C. $+5$
• D. $+3$

Answer 1

Answer: (A)

$-3$ & $+5$

$N{H}_{4}N{O}_3$ exists as $\underset{–}{N}{H}_4^{+}\underset{–}{N}{O}_3^{-}$
Therefore, oxidation numbers of the N are $-3$ and $+5$.