Question

The oxidation numbers of the sulphur atoms in peroxy monosulphuric acid $\left(H_{2}S{O}_5\right)$ and peroxydisulphuric and $\left(H_2{S}_2{O}_8\right)$ are respectively.

• A. $+8$ and $+7$
• B. $+3$ and $+3$
• C. $+6$ and $+6$
• D. $+4$ and $+6$

Answer 1

The correct option is C $+6$ and $+6$

By looking the structure of $H_{2}S{O}_5$, we can observe that there are two oxygen atoms which are linked by peroxide linkage so their oxidation numbers are -1.Rest oxygen atoms attached normally so their oxidation state is -2. The oxidation number of hydrogen is +1.So oxidation number of sulphur is

$2(+1)+x+2(-1)+3(-2)=0,x=+6$

By looking the structure of $H_2{S}_2{O}_8$, we can observe that there are two oxygen atoms which are linked by peroxide linkage so their oxidation numbers are -1.Rest oxygen atoms attached normally so their oxidation state is -2. Oxidation number of hydrogen is +1.So oxidation number of sulphur is

$2(+1)+2\left(x\right)+2(-1)+6(-2)=0,x=+6$