Question

The oxidation potential of a hydrogen electrode at $pH=10$ and $P_{H_2}=1$ is:

• A. $+0.51V$
• B. $0.00V$
• C. $+0.590V$
• D. $+0.059V$

Answer 1

The correct option is C $+0.590V$

According to Nernst equations,

$\frac{1}{2}{H}_2⟶H^{+}$

$E=E^o-\frac{0.0591}{n}logQ$

$E_{OP}=E_{OP}^o-\frac{0.059}{1}log\frac{\left[H^{+}\right]}{P_{H_2}}$

$\because \left[H^{+}\right]={10}^{-10};P_{H_2}=1atm$

$E_{OP}=0+0.059\times 10V$

$E_{OP}=0.59V$