The oxidation potential of a hydrogen electrode at $p H = 10$ and $P_{H_{2}}$ = 1 atm is:

- 0.59 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.00 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 0.59 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+ 0.118 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $+ 0.59 V$
As we know, for hydrogen

$E_{o x i d a t i o n} = 0.059 \times p H = 0.059 \times 10 = 0.59 V$

Suggest Corrections

Similar questions

The Oxidation potential of hydrogen electrode at $P^{H} = 10$ and $P_{H_{2}}$ at 1atm is :

_{H_{2}}

- 0.118 V

H_{2}

p H = 1

T = 298 K

25^{o} C

(P_{H_{2}} = 1

H^{+} = 0.1 M)

Join BYJU'S Learning Program