The oxidation potential of $Z n, C u, A g, H_{2}$ and $N i$ are 0.76, -0.34, -0.80, 0, 0.55 volt respectively. Which of the following reaction will provide maximum voltage?

Z n + {C u}^{2 +} ⟶ C u + {Z n}^{2 +}

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Z n + 2 {A g}^{+} ⟶ 2 A g + {Z n}^{2 +}

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H_{2} + {C u}^{2 +} ⟶ 2 H^{+} + C u

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H_{2} + {N i}^{2 +} ⟶ 2 H^{+} + N i

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Solution

The correct option is A $Z n + 2 {A g}^{+} ⟶ 2 A g + {Z n}^{2 +}$
$Z n + {2 A g}^{+} ⟶ 2 A g + {Z n}^{2 +}$ :

This reaction wil provide maximum voltage and $Z n$ has max. Oxidation potential to tendency to undergo oxidation and for $A g$ minimum oxidation so tendency to go reduction is maximum resulting in providing maximum potential.

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Similar questions

Z n, C u, A g, H_{2}

N i

0.76, - 0.34, - 0.80, 0

0.25

The standard reducation potentials of

$Z n^{2 +} | Z n, C u^{2 +} | C u$ and $A g^{+} | A g$

are respectively -0.76, 0.34 and 0.8 V. The following cells were constructed.

a) $Z n | Z n^{2 +} | | C u^{2 +} | C u$

b) $Z n | Z n^{2 +} | | A g^{+} | A g$

c) $C u | C u^{2 +} | | A g^{+} | A g$

What is the correct order $E {^{0}}_{c e l l}$ of these cells?

Z n + C u^{2 +} \to Z n^{2 +} + C u

M g + Z n^{2 +} \to M g^{2 +} + Z n

C u + 2 A g^{+} \to C u^{2 +} + 2 A g

Z n | Z n^{2 +} (0.001 M) | | C u^{2 +} (0.1 M) | C u

C u / C u^{2 +}

Z n / Z n^{2 +}

For cell reaction, $Z n + C u^{2 +} \to Z n^{2 +} + C u,$ cell representation is

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