The oxidation state and covalency of $A l$ in ${[{A l C l (H_{2} O)}_{5}]}^{2 +}$ are respectively:

+ 6, 6

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+ 3, 6

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+ 2, 6

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+ 3, 3

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Solution

The correct option is B

+ 3, 6

In aqueous solution. The water molecules are just interacting electrostatically, and not actually bonding. Their partially negative end is pulled by aluminum's + 3 oxidation state in an ion-dipole interaction. Cl − is similarly pulled by Al 's + 3 oxidation state

Oxidation state of Al in given compound x+(-1)+5(0) = +2 x = +3 while covalency is 6.

The oxidation state and covalency of

{[{A l C l (H_{2} O)}_{5}]}^{2 +}

are +3, 6 respectively.

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Similar questions

Q. The oxidation state and co-valency of

A l

[A l C l (H_{2} O)_{5}]^{2 +}

, respectively are:

Q. The oxidation state and valency of

A l

[A l C l (H_{2} O)_{5}]^{2 +}

If A = {1, 3, 6}, B = {4, 8} then A x A is

A l + M n O_{4}^{-} \to A l (O H)_{4}^{-} + M n O_{2}

For this reaction the oxidation state of

A l

and

M n

in the product are respectively:

A l + M n O_{4}^{-} \to A l (O H)_{4}^{-} + M n O_{2}

For the above reaction , the oxidation state of

A l

and

M n

in the reactant are respectively:

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The oxidation state and covalency of Al in [AlCl(H2O)5]2+ are respectively:

The oxidation state and covalency of $A l$ in ${[{A l C l (H_{2} O)}_{5}]}^{2 +}$ are respectively: