The oxidation state (integer) of chlorine in perchlorie acid $(H C l O_{4})$ is:

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Solution

The oxidation number of $H = + 1$ .
There is one $H$ atom: $(1) (+ 1) = + 1$ .
The oxidation number of $O$ is $- 2$ .
There are four $O$ atoms here: $(4) (- 2) = - 8$
Therefore, the oxidation state of $C l$ is $+ 7$ .

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