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Coordination and Oxidation Number

The oxidation...

Question

The oxidation state of $A, B,$ and $C$ in a compound are $+ 2, + 5$ and $- 2$ respectively. The compound is :

A_{2} {(B C)}_{2}

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A_{2} {(B C)}_{3}

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A_{3} {({B C}_{4})}_{2}

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A_{2} {({B C}_{4})}_{3}

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Solution

The correct option is C $A_{3} {({B C}_{4})}_{2}$
The oxidation state of A, B, and C in a compound are +2, +5 and −2 respectively. The compound is $A_{3} (B C_{4})_{2}$ .
Total charge on one $B C_{4}$ unit will be $(+ 5 + 4 (- 2)) = - 3$ . Total charge on two such units will be $2 (- 3) = - 6$
Total charge on 3 ions of A will be $3 \times 2 = + 6$
Thus, the positive charges are balanced with negative charges.

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