The oxidation state of $A l$ in $A l C l_{3}$ is

-3

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-2

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Solution

The correct option is B
+3

In compounds formed by union of metals with non-metals, the metal atoms will have positive oxidation numbers and the non-metals will have negative oxidation numbers. Also, the oxidation number of alkali metals ( $L i, N a, K$ etc.) is always +1 and those of alkaline earth metals ( $B e, M g, C a$ etc) is +2.

Let the oxidation number of Aluminum = n

The halogen atoms being much more electronegative, will have -1 oxidation state each.

$⟹$ n + 3 $\times$ (-1) = 0
Or n = +3

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