The oxidation state of Barium in $B a (H_{2} {P O}_{2})_{2}$ is:

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-1

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Solution

The correct option is B 2
$B a (H_{2} {P O}_{2})_{2} = 0$
here oxidation state of $P = + 1$ , $H = + 1$ , and $O = - 2$
$x + (- 1)_{2} = 0 \Rightarrow x = + 2$

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