Question

The oxidation state of chromium in $\left[Cr{\left(PP{h}_3\right)}_3{\left(CO\right)}_3\right]$ is :

• A. $+3$
• B. $+8$
• C. $0$
• D. $+5$

Answer 1

The correct option is C $0$

Let $x$ be the oxidation state of $Cr$ in $\left[Cr\right(PP{h}_3{)}_3(CO{)}_3$.
Since, the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore, $x+3\left(0\right)+3\left(0\right)=0$
or, $x=0$.
Hence, the oxidation state of $Cr$ in $\left[Cr\right(PP{h}_3{)}_3(CO{)}_3$ is $0$.