The oxidation state of chromium in the final product formed by the reaction between KI and acidified potassium dichromate solution is

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Solution

The correct option is D 3
$K_{2} C r_{2} O_{7} + 6 K I + 7 H_{2} S O_{4} \to 4 K_{2} S O_{4} + C r_{2} (S O_{4})_{3} + 7 H_{2} O + 3 I_{2}$
${* C r}_{2} (S O_{4})_{3} \to + 3 2 C r + 3 S O_{4}^{2 -}$

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The oxidation state of chromium in the final product formed by the reaction between KI and acidified potassium dichromate solution is:

I_{2}

S O_{2}

The products formed when $S O_{2}$ reacts with acidified potassium dichromate solution is :

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