The oxidation state of $C r$ in $K_{2} C r_{2} O_{7}$ is:

+ 4

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+ 3

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+ 6

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+ 5

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Solution

The correct option is D $+ 6$
$K_{2} C r_{2} O_{7}$

Let the oxidation state of $C r$ is $x$ .

$2 (+ 1) + 2 x + 7 (- 2) = 0$

$+ 2 + 2 x - 14 = 0$

$2 x - 12 = 0$

$2 x = 12$

$x = + 6$

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