Question

The oxidation state of iron in $N{a}_4\left[Fe\right(CN{)}_5\left(NOS\right)]$ is

• A. $+1$
• B. $+2$
• C. $+3$
• D. Zero

Answer 1

Answer: (B)

$+2$

The compound given is: ${Na}_4\left[Fe{\left(CN\right)}_5\left(NOS\right)\right]$,

Let, oxidation number of $Fe=x$

Oxidation number of $CN=-1$

Oxidation number of $NOS=-1$

Therefore, $x+(-1)\times 5+1(-1)=-4$

$x-5-1=-4$

$x=+2$