The oxidation state of mercury in amalgam, calomel and corrosive sublimate is:

0, +1, +2

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+1, +1, +2

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+1, +2, +1

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0, +1, +1

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Solution

The correct option is A 0, +1, +2
In amalgam, mercury has 0 oxidation state
Calomel is $H g_{2} C l_{2}$ in which $H g$ oxidation state is +1
Corrosive sublimate is $H g C l_{2}$ in which $H g$ oxidation state is +2

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