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Variable Oxidation States

The oxidation...

Question

The oxidation state of Mn giving pink precipitate on treating with NaOH is :

A

5+

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B

3+

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C

2+

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D

None of the above

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Solution

The correct option is C 2+
$M n^{2 +}$ belongs to group 3 cations. A pink (flesh-like) precipitate indicates $M n^{2 +}$ . To a fresh sample, add NaOH: white precipitate, which turns darker on standing: $M n^{2 +}$ present.

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Q. Paragraph for below question

नीचे दिए गए प्रश्न के लिए अनुच्छेद

Mⁿ⁺ + NaOH → x↓

x exposure to - ----- \to air y ↓

M^{n +} N a_{2} S - -- \to z ↓

z HCl - - \to A ↑

When Mⁿ⁺ is treated with hexacyanoferrate(II), it gives precipitate under ordinary atmospheric condition.

Mⁿ⁺ + NaOH → x↓

M^{n +} N a_{2} S - -- \to z ↓

z HCl - - \to A ↑

जब Mⁿ⁺ को हेक्सासायनोफेरैट(II) के साथ उपचारित किया जाता है, तो यह सामान्य वायुमण्डलीय परिस्थिति में अवक्षेप देता है।

Q. Basic radical Mⁿ⁺, precipitate y and colour of precipitate z is,

प्रश्न - क्षारीय मूलक Mⁿ⁺, अवक्षेप y तथा अवक्षेप z का रंग है

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