The Oxidation state of Mn in $K_{2} M n O_{4}$ is

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Solution

The correct option is D 6
O. S. (O) =-2
O.S. (K) =+2 (alkali metal)
$K_{2} M n O_{4} \Rightarrow 2 (1) + n - 2 (4) = 0$
n =8-2 =+6
So, oxidation state of Mn is +6

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