The oxidation state of Mo in its oxo-complex species $[M o_{2} O_{4} (C_{2} H_{4})_{2} (H_{2} O)_{2}]^{2 -}$ is :

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Solution

The correct option is B 3
The oxidation state of Mo in its oxo-complex species

$[M o_{2} O_{4} (C_{2} H_{4})_{2} (H_{2} O)_{2}]^{2 -}$ is $+ 3$ .

$H_{2} O, C_{2} H_{4}$ are neutral ligand having charge 0 and charge on $O$ is -2

2x +(-24) + (02)+(0*2) =(-2)

2x -8 = -2

2x = -2 +8

2x = 6

x = 3
Option (B) is correct.

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Similar questions

[M o_{2} O_{4} (C_{2} H_{4})_{2} (H_{2} O_{2})]^{2 -}]

M o

[M o_{2} O_{4} (C_{2} H_{4})_{2} (H_{2} O)_{2}]^{2 -}

_{2}

_{4}

_{2}

_{4}

_{2}

_{2}

_{2}

^{2 -}

\frac{- 1}{2}

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