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Question

The oxidation state of molybdenum in its oxo complex species [Mo2O4(C2O4)2(H2O)2]2− is:

A
+ 2
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B
+ 3
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C
+ 4
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D
+ 5
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Solution

The correct option is B + 3
From structure, it can be seen that, oxidation state of Mo =84+2x=2.
So, x=+5 .

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