The oxidation state of molybdenum in its oxo complex species $[M o_{2} O_{4} (C_{2} H_{4})_{2} (H_{2} O_{2})]^{2 -}]$ .

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Solution

The correct option is B 3
Let the oxidation number of molybdenum $(M o)$ be $x$ .
Oxidation number of $H_{2} O_{2} = C_{2} H_{4} = 0$ , $O = - 2$ .
In $[M o_{2} O_{4} (C_{2} H_{4})_{2} (H_{2} O_{2})]^{2 -}$
$2 x + 4 \times (- 2) + 2 \times 0 + 0 = - 2$
$2 x - 8 = - 2$ or $x = + 3$
The oxidation state of molybdenum in its oxo complex species $[M o_{2} O_{4} (C_{2} H_{4})_{2} (H_{2} O_{2})]^{2 -}$ is +3

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