Question

The oxidation state of $N$ in $NaN{O}_3$ is $+x$. Here, $x$ is :

Answer 1

Let $x$ be the oxidation state of $N$ in $NaN{O}_3$.
Since the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore, $+1+x+3(-2)=0$
or, $x=+5$