The oxidation state of Na- K- Rb respectively in N a 2 O 2- KO 2- RbO 2 is -A- -1-1-1B- -1-1-1C- -1-1-1D- -1-1-1

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Chemical Reactivity (Group 1)

The oxidation...

Question

The oxidation state of Na, K, Rb respectively in $N a_{2} O_{2}, K O_{2}, R b O_{2}$ is :

+1, +1, +1

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+1, -1, +1

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+1, +1, -1

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-1, -1, -1

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K_{2} O

K_{2} O_{2}

K O_{2}

C a O C l_{2}

{K O}_{2}, {C s O}_{2}

{R b O}_{2}

- \frac{1}{2}

+ 1

\frac{1}{2}

O_{2}^{-}

(O)

H_{2} O_{2} a n d K O_{2}

\frac{(1 + i)^{n}}{(1 - i)^{n - 2}}

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