The oxidation state of nitrogen in dinitrogen trioxide is:

+ 1

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+ 2

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+ 3

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+ 4

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Solution

The correct option is C $+ 3$
Dinitrogen trioxide is $N_{2} O_{3}$ .

The oxidation state of nitrogen in $N_{2} O_{3}$ is:

$2 \times x + 3 \times (- 2) = 0$

$x = + 3$

Therefore, option $C$ is correct.

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