Question

The oxidation state of O in $O{F}_2$is:

• A. -2
• B. +2
• C. -1
• D. +1

Answer 1

The correct option is B

+2

Since the molcule is neutral, the sum of the oxidation numbers of all the elements is equal to 0.
The oxidation number of F (Flourine) is -1
Let the oxidation number of O be $n$.
So if we take the sum of oxidation numbers of the elements we get the equation
$n+2(-1)=0$

$n=+2$
Hence, the oxidation number of oxygen in $O{F}_2$ is +2.

Note: If the element that oxygen combines with is more electronegative than oxygen then oxygen can have a positive oxidation number.