Question

The oxidation state of the underlined element in the given compound is:

$\underset{–}{C_{12}}{H}_{22}{O}_{11}$

• A. 5
• B. 4
• C. 0
• D. none of these

Answer 1

The correct option is C 0

$C_{12}{H}_{22}{O}_{11}$= Sucrose

$\Rightarrow 12x+22\times 1-11\times 2=0$

$\Rightarrow 12x+22-22=0$

$\Rightarrow x=0$ .