The oxidation states of nitrogen in $N O, N O_{2}, N_{2} O and N O_{3}^{-}$ are in the order of

N O_{2} > N O_{3}^{-} > N O > N_{2} O

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N_{2} O > N O_{2} > N O > N O_{3}^{-}

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N O_{3}^{-} > N O_{2} > N O > N_{2} O

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N O > N O_{2} > N O_{3}^{-} > N_{2} O

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Solution

The correct option is C $N O_{3}^{-} > N O_{2} > N O > N_{2} O$
Answer: (c):

Oxidation state of $^{'} N^{'}$
$N O \to + 2$
$N O_{2} \to + 4$
$N_{2} O \to + 1$
$N O_{3}^{-} \to + 5$

Decreasing order of oxisation state of 'N' is as follows

$N O_{3}^{-} > N O_{2} > N O > N_{2} O$

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