The oxidation states of P atom in $P O C l_{3}, H_{2} P O_{3} a n d H_{4} P_{2} O_{6}$ , respectively, are

+5, +4, +4

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+5, +5, +4

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+4, +4, +5

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+3, +4, +5

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Solution

The correct option is A +5, +4, +4
The oxidation number of P atom in $P O C l_{3}, H_{2} P O_{3} a n d H_{4} P_{2} O_{6}$ , respectively, are +5,+4, +4.
$P O C l_{3}$
x - 2 -3 = 0
x = 5
$H_{2} P O_{3}$
2 + x - 6 = 0
x = 4
$H_{4} P_{2} O_{6}$
4 + 2x - 12 = 0
2x = 8
x = 4

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