Question

The oxidation states of P atom in $POC{l}_3,H_{2}P{O}_{3}and{H}_4{P}_2{O}_6$ , respectively, are

• A. +5, +4, +4
• B. +5, +5, +4
• C. +4, +4, +5
• D. +3, +4, +5

Answer 1

The correct option is A +5, +4, +4

The oxidation number of P atom in $POC{l}_3,H_{2}P{O}_{3}and{H}_4{P}_2{O}_6$ , respectively, are +5,+4, +4.
$POC{l}_3$
x - 2 -3 = 0
x = 5
$H_{2}P{O}_3$
2 + x - 6 = 0
x = 4
$H_4{P}_2{O}_6$
4 + 2x - 12 = 0
2x = 8
x = 4