Question

The oxidation states of the most electronegative element in the products of the reaction $Ba{O}_2$ with dil. $H_{2}S{O}_4$ are :

• A. 0 and -1
• B. -1 and -2
• C. -2 and 0
• D. -2 and +1

Answer 1

Answer: (B)

-1 and -2

products of the reaction $Ba{O}_2$ with dil. $H_{2}S{O}_4$ are :

$Ba{O}_2+H_{2}S{O}_4\to BaS{O}_4+H_2{O}_2$.

The oxidation states of the most electronegative element in the products of the reaction is -1 and -2 respectively.

Hence option B is correct.